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Posted by RW Salnick on June 12, 2008, 11:00 am
Please log in for more thread options nicksanspam@ece.villanova.edu brought forth on stone tablets:
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>>Does anyone by chance have a price, or know of a place selling them that
>>actually tells you the price up front, for a vertical axis windmill large
>>enough to power a 2,000 square foot grid connected home in a 10 MPH
>>average wind?
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> An average US house uses about 800 kWh/mo, about 1100 watts on a continuous
> basis, and page 36 of Paul Gipe's 1993 Wind Power book says the wind power
> density with a Rayleigh speed distribution is 0.104V^3 W/m^2, where V is
> the average windspeed in mph and the best rotors achieve 40% efficiency
> (vs the 60% Betz limit)... 90% efficiencies for the transmission, generator,
> and power conversion make the wind power density 0.0303V^3 W/m^2, or 30.3
> W/m^2 at 10 mph, so you might have 1100/30.3 = 36 m^2 of swept area, eg
> a 22 foot diameter circular windmill, comparable to the size of the house.
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> I don't know where to buy one of these, but you might make a high-speed,
> 6-blade double-delta Darrieus rotor with 2 tetrahedra joined on a horizontal
> face, rotating on 2 points, with an automobile wheel at the top and another
> at the bottom, attached to a 5:1 step-up auto rear with the spider gears
> welded together, with more stepup for an induction motor that could act as
> a motor to start the rotor.
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> It might have 6 galvanized steel tubes and 6 thin, low-solidity dacron
> sailcloth sailblades with the leading edges wrapped around the tubes and
> trailing edges attached to 6 wires. A tension ring with 3 horizontal wires
> could connect 3 points halfway up to give the windmill vertical support,
> and 3 guy wires could hold down a pillow hlock at the top.
>
> Good luck :-)
>
> Nick
>
Interesting design. But multiply by two for required area - VAWTs only
use half the swept area (in fact, it is worse than that, since the
advancing side adds drag, but who's counting?)
bob
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