Posted by Home Guy on April 15, 2011, 2:47 pm
I did, you dumbass #2.
Go and read my last post.
And note what happens when the voltage sources have unequal voltages.
And note that we are not talking about batteries here in the case of a
municipal power grid and a PV system.
If that diagram shows reverse current flow because Battery 1 has a lower
voltage than Battery 2 (and current I1 is negative), then at what point
does current I1 become zero? What would the voltage of battery 1 have
to be for current I1 to be zero?
Posted by Jim Wilkins on April 15, 2011, 4:48 pm
Considering the level of this discussion when the solutions are simple
algebra, you aren't ready to handle the analytical geometry and
differential equations of AC circuit analysis.
Posted by Jim Wilkins on April 15, 2011, 5:11 pm
This is a good example:
"Now that we've seen how series and parallel AC circuit analysis is
not fundamentally different than DC circuit analysis,..."
Electrical engineers use j instead of i for the square root of -1
because i has long been the standard for Current (intensity). In this
instance the imaginary number is an excellent tool to analyze real-
world physical phenomena.
Posted by firstname.lastname@example.org on April 15, 2011, 6:12 pm
I have read your posts and like most other people here
have concluded you are wrong, so I don't see why
you're calling ME the dumbass.
Uh, huh. I have noted that and if you have any questions about how
that works, I'll be happy to answer them. I'm still waiting for your
answer about the case with EQUAL voltages. That was the essence
of your argument, was it not? That a power source can't provide
power in parallel with another unless it raised the voltage? So,
leave everything else the same and just make the voltage sources
equal. Tell us what current flows through the load resistor and what
currents flow through each voltage source. This is EE course circuit
theory course 101, about the first week.
BTW, you have an engineering degree?
Yes and since you seem incapable of understanding a simple
circuit that represents 2 batteries connected in parallel to a
load, no need to add the additional complexities.
I see you do have a question.
Simple. With no current flow through battery 1, then the circuit
is reduced to an ideal voltage source connected to two resistors
in series. One of these represents the internal resistance of
battery 2 and is 20 ohms. The other is the load resistor of 40
ohms. So, we have 20 volts across 60 ohms, giving a
current of .333Amps. That .333amps produces a voltage of
13.34 across the load resistor. (.333 A X 40ohms.) That means
voltage source V1 would have to be at the same potential,
13.34 volts and when it is, no current flows through what
represents battery 1.
I've answered your question, now answer mine:
What are currents I1, I2, I3 when the voltage sources V1 and V2
are both 20 volts.
Posted by email@example.com on April 15, 2011, 11:33 pm
If he really means unequal voltage then he's proving my point. He's a dumbass
(second point proven).