Posted by John Fields on August 14, 2009, 11:50 am
wrote:
>> wrote:
>>
>>>On Mon, 10 Aug 2009 22:05:42 -0400, clare@snyder.on.ca wrote:
>>>
>>>>
>>>>The 6 amp motor means it draws 6 amps from the mains. It does not mean
>>>>ANYTHING as far as how much power it produces, other than that it
>>>>cannot produce more than 690 watts at 115 volts
>>>
>>>Have you returned to constant current power distribution with 6 A
>>>circuits ?
>>>
>>>Arc lamps in the 1880's were specified by the number of amperes
>>>(typically 6 A for street lighting). All lamps were series connected
>>>and you could operate 20-25 of these in series from a 6 A DC generator
>>>producing a 1000-1500 V DC loaded voltage. Thus, the voltage drop
>>>across each arc lamp was about 55 V on average.
>>>
>>
>> We have a winner.
>What? That bologna is a winner?
---
Can you say: "Tongue in cheek?"
---
>Then you don't know much about Wattage and AMP.
>This is what is wrong with your winner:
>>>>ANYTHING as far as how much power it produces, other than that it
>>>>cannot produce more than 690 watts at 115 volts
---
Huh???
It's clear to me that if the motor load is resistive and draws 6 amperes
from 115VRMS mains, then the power delivered to a nonreactive mechanical
load cannot be greater than:
P = IE = 6A * 115V = 690 watts.
As a matter of fact, (so far) the three basic laws of thermodynamics
are:
1. You can't win.
2. You can't break even
3. You can't get out of the game
So, for 690 watts taken from a source, what will be delivered to the
eventual load will depend on the price exacted by the delivery system.
---
>600watt can be any form of voltage, it is a combined Voltage and AMP together
to form a power
>of 600watt, you can't say it's fixed to 115V.
---
True, but still utter nonsense since we draw power from a voltage source
which _is_ fixed at 120V.
That means that no matter how much power we ask the source to deliver,
it will deliver it into a load which is designed to drop 120V at its
required power
---
>12VDC can light up a 600watt light bulb too.
---
Sure, if the 12VDC source can supply 50 amperes into the load without
sagging, but so what?
---
>Yup, now you just confirm that you American are jerks!
---
I think what's been confirmed is that you're an idiot and, consequently,
that your opinions are irrelevant.
JF
Posted by You on August 14, 2009, 5:44 pm
> It's clear to me that if the motor load is resistive and draws 6 amperes
> from 115VRMS mains, then the power delivered to a nonreactive mechanical
> load cannot be greater than:
Sonny, there is NO SUCH THING as a pure Resistive for a Motor.......
Posted by John Fields on August 14, 2009, 6:55 pm
>> It's clear to me that if the motor load is resistive and draws 6 amperes
>> from 115VRMS mains, then the power delivered to a nonreactive mechanical
>> load cannot be greater than:
>Sonny, there is NO SUCH THING as a pure Resistive for a Motor.......
---
Even if its inductance is tuned out?
JF
Posted by Archimedes' Lever on August 15, 2009, 1:14 am
>> It's clear to me that if the motor load is resistive and draws 6 amperes
>> from 115VRMS mains, then the power delivered to a nonreactive mechanical
>> load cannot be greater than:
>Sonny, there is NO SUCH THING as a pure Resistive for a Motor.......
Yes, there is.
A rail gun is a linear motor, and there is ZERO inductance involved.
Mag lev is resistive as well, since it is a DC field on the levitation
coils.
There are other examples. Piezo comes to mind.
Sonny? Jeez, ya retarded fuck, get a clue.
Posted by harry on August 15, 2009, 6:40 pm
wrote:
> >> It's clear to me that if the motor load is resistive and draws 6 amperes
> >> from 115VRMS mains, then the power delivered to a nonreactive mechanical
> >> load cannot be greater than:
> >Sonny, there is NO SUCH THING as a pure Resistive for a Motor.......
> Yes, there is.
> A rail gun is a linear motor, and there is ZERO inductance involved.
> Mag lev is resistive as well, since it is a DC field on the levitation
> coils.
> There are other examples. Piezo comes to mind.
> Sonny? Jeez, ya retarded fuck, get a clue.
All electric motors whether linear or rotating have an associated
magnetic field an hence are inductors.
A rail gun is inductive, hugely so. There is a single turn coil
(formed by the two rails and the projectile) and tens of thousands of
amps. It's only the magnetic field makes it work.
A linear motor is just an induction motor "cut" axially and laid out
flat.
Mag Lev is not a motor. No work is done. (Apart from the initial lift)
Neither is piezo a motor. And even a piezo electric crystal has
inductance.
XML site map
>>
>>>On Mon, 10 Aug 2009 22:05:42 -0400, clare@snyder.on.ca wrote:
>>>
>>>>
>>>>The 6 amp motor means it draws 6 amps from the mains. It does not mean
>>>>ANYTHING as far as how much power it produces, other than that it
>>>>cannot produce more than 690 watts at 115 volts
>>>
>>>Have you returned to constant current power distribution with 6 A
>>>circuits ?
>>>
>>>Arc lamps in the 1880's were specified by the number of amperes
>>>(typically 6 A for street lighting). All lamps were series connected
>>>and you could operate 20-25 of these in series from a 6 A DC generator
>>>producing a 1000-1500 V DC loaded voltage. Thus, the voltage drop
>>>across each arc lamp was about 55 V on average.
>>>
>>
>> We have a winner.
>What? That bologna is a winner?
---