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Posted by Tom P on May 5, 2012, 4:43 pm
I've been half following some of the discussions on this group, maybe
someone can fill me in some details.

  I've gotten the impression that the way these things work is by
accelerating deuterium or tritium ions so that enough collisions occur
to release energy.

So we have for example:
1D2 + 1D2 -->2He3 (0.82 MeV) + 0n1 (2.45 MeV)

This reaction is actually used in a commercial neutron generator, so in
terms of proof of principle, so far so good.  There are other reactions,
but let's take this as a working example.

Where I get unstuck is with the numbers. The commercial device in
question consumes around 2-3 kW of power and produces 10^7 neutrons per
That means that as a by-product, it produces 10^7 x 2.45 MeV, or
24500000 MeV of energy per second.
That sounds a lot, but if you convert into watts and joules that comes
out as 0.000003925334385 watts. Hmm.

Ok, well let's suppose that we could up the efficiency by a factor of
several million so that it produces more energy than it consumed - say
10kW. That's 62415064799632350 MeV per second, so you would be
generating around 6x10^24 neutrons per second. These neutrons are also
carrying the energy that you are trying to capture, so you'll need a
suitable moderator to slow them, say water, and something to absorb
them. Whatever absorbs them needs to do so extremely efficiently so that
you don't get too many neutrons leaking out of your basement and making
your entire house radioactive, not to mention your wife and kids.

  Maybe there's some other technology, but the bottom line is that it
seems you have a lot of neutrons to look after, and this doesn't really
sound like a sound DIY project to me.
Can someone comment?  Are my numbers all wrong?

Posted by Vaughn on May 6, 2012, 1:50 am
On 5/5/2012 12:43 PM, Tom P wrote:

Your assumption on the physics of the reaction must be wrong.  From what
I've read, those things don't generate any significant number of
neutrons.  Take it from an old nuke, no government is about to allow you
to have any significant generator of neutrons in your basement.


Posted by j on May 6, 2012, 1:12 pm
 On 5/5/2012 9:50 PM, Vaughn wrote:

More here:


The key is providing sites in the catalyst for nuclear reactions (not
necessarily fusion) to take place.


  Take it from an old nuke, no government is about to allow you

Posted by Tom P on May 6, 2012, 1:57 pm
 On 05/06/2012 03:12 PM, j wrote:

Jeff,just  what kind of nuclear reactions are you talking about, if not
fusion? Just show me a simple equation like this one:
1D2 + 1D2 -->2He3 (0.82 MeV) + 0n1 (2.45 MeV)

Posted by Morris Dovey on May 6, 2012, 2:44 am
 On 5/5/12 11:43 AM, Tom P wrote:

Everybody can comment.  ;-)

I'm doing an amateur investigation of one of the "other reactions" -
specifically the Ni/H reaction with which Andrea Rossi (and a few
others) have claimed to produce heat output in excess of heat input, and
with which Rossi has claimed to produce a self-sustaining reaction.

You can find all that is publicly known buried under heaps of ignorant
speculation by doing a Google search on Rossi+ECat+LENR.

There appears to be a growing acceptance in the physics community that
there's /some/ kind of nuclear reaction taking place, but I haven't seen
any movement toward consensus concerning reaction specifics.

I don't have much interest in the physics. I have need of a compact heat
source that can operate for extended periods of time in a third-world
context without a reliable fuel distribution network, and am
willing/able to expend a limited amount of personal resource to discover
whether or not a Ni/H LENR can satisfy my requirement.

Since it's one of your concerns, Rossi and all of the observers have
reported that radiation is not a problem, and that the Ni/H reaction
produces no unstable isotopes. Still, it struck me as prudent to
incorporate Geiger-Müller detector input and program the controller to
do an automatic shutdown if a high count (three times a normal
background peak) is detected in any one-second interval.

Rossi is claiming to produce about 5kW output from a reactor containing
50 grams of fine nickel powder, and it appears that an initial charge of
hydrogen (~50cc) will run his reactor for 4-5 hours. In one of the
interview transcripts I read, he said that the 50 grams of nickel would
power his reactor for about 6 months of operation at that power level.

It all just begs for testing.

Morris Dovey

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