Posted by Curbie on January 2, 2011, 3:21 am
daestrom,
Thanks, I've read a bunch of Heat-X books and still haven't found what
I'm looking for.
Curbie
>On 12/30/2010 17:57 PM, Curbie wrote:
>> daestrom,
>>
>> I'm sort of gummed up with some of my distillation calculations,
>> mainly for water to water and maybe oil to water heat exchangers
>> (re-biolers) and vapor to water condensers. Could you recommend a good
>> heat-X book with completed math examples in imperial units?
>>
>> Thanks,
>>
>> Curbie
>>
>I have one at work, will look up the biblio on it next week when I'm
>back at work.
>IIRC, condensers are *majorly* affected by even traces of
>non-condensable gasses (i.e. air). Tends to build up as a boundary
>layer on the cooling surface and then you're limited by diffusion of
>vapor through the film layer of air.
>This is why steam condensers have the air-removal system suction
>embedded in the middle of the tube bundle (sometimes called a 'dry pipe
>suction'). Taking suction from the coldest spot improves the
>air-fraction in the suction flow.
>daestrom
Posted by Morris Dovey on January 5, 2011, 1:27 am
On 12/30/2010 3:29 PM, daestrom wrote:
> I also have "Thermodynamics: 4th Edition" by Wark (1983). Don't know if
> it's exactly the same one, it doesn't mention a 'Richards'. I've got
> about five different thermo books and a couple of heat-transfer ones.
"Thermodynamics" (6e) arrived this afternoon. Richards is an ME prof at
Rose-Hulman, and I gathered that Wark (at Purdue) brought Richards in to
broaden the presentation. It's interesting to me because I studied
(math) at Rose and my first full-time job was managing their computing
center.
--
Morris Dovey
http://www.iedu.com/DeSoto/
PGP Key ID EBB1E70E
Posted by J. Clarke on December 31, 2010, 1:37 am
>
> On 12/30/2010 9:37 AM, daestrom wrote:
>
> > This is an old text book but still very relevant. I've always liked
> > stuff by Burghardt for two reasons. The math he presents is
> > straight-forward algebra and doesn't leave you glassy-eyed. He uses
> > 'English' units with the lb-force and lb-mass convention, which is what
> > I first started out with.
>
> Heh! Straight-forward algebra sounds good 'cause I'm not allowed to haze
> out on math.
>
> I'm doing my level best to stick to SI units, so what amounts to an "old
> friend" to you is sheer aggravation for me. I suppose I should learn to
> be comfortable with both, but doubt I can manage that _and_ actually
> solve the problems in front of me...
>
> > There's a good section on gas laws and various 'processes'. And lots of
> > information in the appendices. One area it's a bit 'light' in is the
> > heat-transfer stuff, but it does cover the basics of that as well.
> >
> >
(Amazon.com product link shortened)
>
> I've bookmarked it. The books already en route are
>
> "Thermodynamics" by Wark and Richards, and
>
> "Steam Tables: Thermodynamic Properties of Water Including Vapor, Liquid
> and Solid Phases" by Hill, Keenan, Moore, and Keyes
>
> ...and I'm already at the point where putting another book on the shelf
> means that one of the books already there has to go. :(
>
> Wouldn't it be great if someone developed a gizmo that ate paper books
> and spit out e-books on flash memory sticks? (Even better if
> high-lighting and marginal notes were preserved!) :)
>
> > Happy New Year
>
> Peace, health, prosperity, and sunshine to you.
You might want to check Pirate Bay for any titles you need as ebooks.
An amazing variety of engineering and scientific texts have been scanned
and torrented by various people. Most of them are image files, not
searchable text, though.
Posted by Curbie on December 24, 2010, 8:18 pm
Morris,
I'm bouncing between the kitchen and computer preparing for two Skype
parties, but here is the Gas Law and pressure conversion modules I use
in my spread-sheets, let me know if you don't find the answer there,
and if you want, I'll set-up a sheet to cross-check your math question
in a couple of days.
Curbie
' Gas Law Conversion Routines
' Between (V)olume, (T)emperature, (P)ressure, and (n)mol using the
Gas Law equation.
Option Explicit ' force explicit
declaration of all variables
Public Function GL_R(P As Double, V As Double, T As Double)
' Returns Gas Law Constant (R) for the given Pressure, Volume, and
Temperature based on 1
' atmosphere of pressure, 22.4 liters of volume, and a temperature of
273.15°K or 492°R
' using the Gas Law equation.
' 1. Assume a basis. Assume gas is at standard conditions, that is, 1
g-mol gas at 1 atm
' (101.3 kPa) pressure at 0°C (273°K or 492°R) occupying a volume of
22.4 L.
' 2. Compute the gas constant Apply suitable conversion factors and
obtain the gas constant in
' various units. Use PV=RT; that is. R=PV/T. Thus:
' a. R =(1 atm)[22.4 L/(g-mol)](1000 cm3/L)/273°K = 82.05
(atm)(cm3)/(g-mol)(°K)
' b. R =(14.7 psia)(359 ft3/lb-mol/492°R = 10.73
(psia)(ft3)/(Ib-mol)(°R)
' c. R =(1 atm)[359ft3/(lb-mol)]/273°K = 1.315 (atm)(ft3)/(lb-mol)(°K)
' d. R =[10.73(psia)(ft3)/(lb-mol)(°R)](144 in2/ft2)[3.77x10-7
kWh/(ft-lbf)] = 5.83x10-4 kWh/(lb-mol)(°R)
' e. R =[5.83x10-4 kWh/(lb-mol)(°R)](1/0.746 hp-h/kWh) = 7.82x10-4
hp-h/(lb-mol)(°R)
' f. R =(101.325 kpa/atm)[22.4 L/(g-mol)][1000
g-mol/(kg-mol)]/(273°K)(1000 L/m3) = 8.31 (kpa)(m3)/(kg-mol)(°K)
' g. R= [7.82x10-4 hp-h[(lb-mol)(°R)][6.4162x10+5 cal/(hp-h)][1/453.6
lb-mol/(g-mol)](1.8 °R/K) = 1.99 cal/(g-mol)(°K)
GL_R = (P * V) / T
End Function
Public Function GL_V(P As Double, T As Double, n As Double) As Double
' Returns Volume in Liters for the given Pressure in (kiloPascals),
Temperature (in kelvin), and
' mol using the Gas Law equation.
GL_V = (n * GASR * T) / P
End Function
Public Function GL_P(V As Double, T As Double, n As Double) As Double
' Returns Pressure in KiloPascals for the given Volume (in liters),
Temperature in (kelvin), and
' mol using the Gas Law equation.
GL_P = (n * GASR * T) / V
End Function
Public Function GL_T(V As Double, P As Double, n As Double) As Double
' Returns Temperature in kelvin for the given Volume (in liters),
Pressure (kiloPascals), and
' mol using the Gas Law equation.
GL_T = (P * V) / (n * GASR)
End Function
Public Function GL_n(V As Double, P As Double, T As Double)
' Returns Moles for the given Volume (in liters), Pressure
(kiloPascals), and Temperature in (kelvin)
' using the Gas Law equation.
GL_n = (P * V) / (GASR * T)
End Function
' Pressure Conversion Routines
' Between (A)tmospheres, kilo(P)ascals, (T)orr, milli(B)ars and
(L)Pounds per Square Inch
Option Explicit ' force explicit
declaration of all variables
Public Function CP_A2P(a As Double) As Double
' Returns pressure in kiloPascals for the given pressure in
Atmospheres.
CP_A2P = a * 101.325
End Function
Public Function CP_A2B(a As Double) As Double
' Returns pressure in milliBars for the given pressure in Atmospheres.
CP_A2B = a * 1013.25
End Function
Public Function CP_A2L(a As Double) As Double
' Returns pressure in P.S.I. for the given pressure in Atmospheres.
CP_A2L = a * 14.69595
End Function
Public Function CP_A2T(a As Double) As Double
' Returns pressure in Torr for the given pressure in Atmospheres.
CP_A2T = a * 760
End Function
Public Function CP_P2A(P As Double) As Double
' Returns pressure in Atmospheres for the given pressure in
kiloPascals.
CP_P2A = P * 0.009869233
End Function
Public Function CP_P2B(P As Double) As Double
' Returns pressure in milliBars for the given pressure in kiloPascals.
CP_P2B = P * 10
End Function
Public Function CP_P2L(P As Double) As Double
' Returns pressure in P.S.I. for the given pressure in kiloPascals.
CP_P2L = P * 0.1450377
End Function
Public Function CP_P2T(P As Double) As Double
' Returns pressure in Torr for the given pressure in kiloPascals.
CP_P2T = P * 7.500617
End Function
Public Function CP_B2A(B As Double) As Double
' Returns pressure in Atmospheres for the given pressure in milliBars.
CP_B2A = B * 0.0009869233
End Function
Public Function CP_B2P(B As Double) As Double
' Returns pressure in kiloPascals for the given pressure in milliBars.
CP_B2P = B * 0.1
End Function
Public Function CP_B2L(B As Double) As Double
' Returns pressure in P.S.I. for the given pressure in milliBars.
CP_B2L = B * 0.01450377
End Function
Public Function CP_B2T(B As Double) As Double
' Returns pressure in Torr for the given pressure in milliBars.
CP_B2T = B * 750.0617
End Function
Public Function CP_L2A(l As Double) As Double
' Returns pressure in Atmospheres for the given pressure in P.S.I.
CP_L2A = l * 0.06804596
End Function
Public Function CP_L2B(l As Double) As Double
' Returns pressure in milliBars for the given pressure in P.S.I.
CP_L2B = l * 68.94757
End Function
Public Function CP_L2P(l As Double) As Double
' Returns pressure in kiloPascals for the given pressure in P.S.I.
CP_L2P = l * 6.894757
End Function
Public Function CP_L2T(l As Double) As Double
' Returns pressure in Torr for the given pressure in P.S.I.
CP_L2T = l * 51.71493
End Function
Public Function CP_T2A(T As Double) As Double
' Returns pressure in Atmospheres for the given pressure in Torr.
CP_T2A = T * 0.001315789
End Function
Public Function CP_T2B(T As Double) As Double
' Returns pressure in milliBars for the given pressure in Torr.
CP_T2B = T * 1.333224
End Function
Public Function CP_T2P(T As Double) As Double
' Returns pressure in kiloPascals for the given pressure in Torr.
CP_T2P = T * 0.1333224
End Function
Public Function CP_T2L(T As Double) As Double
' Returns pressure in P.S.I. for the given pressure in Torr.
CP_T2L = T * 0.01933677
End Function
' Global Constants
Public Const BASK = 273.15 ' Base of Kelvin scale °
Public Const BASR = 459.67 ' Base of Rankine scale
°
Public Const GASR = 8.314 ' Gas Law constant
Public Const MF_W = 18.016 ' Atomic Mass of water
equaling One Mol
Public Const MF_M = 32.042 ' Atomic Mass of
methanol equaling One Mol
Public Const MF_E = 46.068 ' Atomic Mass of ehanol
equaling One Mol
Public Const MF_P = 60.094 ' Atomic Mass of
propanol equaling One Mol
Public Const MF_B = 74.12 ' Atomic Mass of butanol
equaling One Mol
Public Const LHVW = 40.639 ' Latent Heat of
Vaporizrion for Water (kJm)
Public Const LHVM = 45.3 ' Latent Heat of
Vaporizrion for Methanol (kJm)
Public Const LHVE = 39.22 ' Latent Heat of
Vaporizrion for Ehanol (kJm)
Public Const LHVP = 40.3 ' Latent Heat of
Vaporizrion for Propanol (kJm)
Public Const LHVB = 4
Posted by Morris Dovey on December 25, 2010, 4:50 pm
On 12/24/2010 2:18 PM, Curbie wrote:
> Morris,
>
> I'm bouncing between the kitchen and computer preparing for two Skype
> parties, but here is the Gas Law and pressure conversion modules I use
> in my spread-sheets, let me know if you don't find the answer there,
> and if you want, I'll set-up a sheet to cross-check your math question
> in a couple of days.
<major snip to file CurbieCalc>
Mmmm - yummy. Some of these I already had but all appear useful (even
though I'm working hard to convert /myself/ to metric only). :)
I think I'm going to transliterate the entire collection to C language
modules in a (growing) C thermodynamics library.
Thanks!
--
Morris Dovey
http://www.iedu.com/DeSoto/
PGP Key ID EBB1E70E
>> daestrom,
>>
>> I'm sort of gummed up with some of my distillation calculations,
>> mainly for water to water and maybe oil to water heat exchangers
>> (re-biolers) and vapor to water condensers. Could you recommend a good
>> heat-X book with completed math examples in imperial units?
>>
>> Thanks,
>>
>> Curbie
>>
>I have one at work, will look up the biblio on it next week when I'm
>back at work.
>IIRC, condensers are *majorly* affected by even traces of
>non-condensable gasses (i.e. air). Tends to build up as a boundary
>layer on the cooling surface and then you're limited by diffusion of
>vapor through the film layer of air.
>This is why steam condensers have the air-removal system suction
>embedded in the middle of the tube bundle (sometimes called a 'dry pipe
>suction'). Taking suction from the coldest spot improves the
>air-fraction in the suction flow.
>daestrom