Hybrid Car – More Fun with Less Gas

Re: Wood stove clearance

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Posted by nicksanspam on March 1, 2005, 6:41 am
 


Thick works better, IMO, but thin is cheaper.

             Ts        Tw
             |    R    |   2/3
600 -- --> --*---www-------www--- 70
        I    |  
             |   1/3
              ---www--- 70

If the stove temp is 600 F, I = 0.1714x10^-8(600+460)^4 = 2164 Btu/h-ft^2.
A 90% reflective shield would absorb about 10% of this, ie 216 Btu/h-ft^2.
The linearized radiation conductance R = 1/(4x0.1714x10^-8(70+460)^3x0.1)
= R9.8, with 2/3 airfilm conductances. Here's one equivalent circuit:


             Ts        Tw
       1/3   |   9.8   |   2/3
    ---www---*---www-------www--- 70 F
   |  
   | 142 F = 70+216x1/3  
  ---
   _      
   |      
   -

What are the shield and wall temps Ts and Tw?

Nick


Posted by nicksanspam on March 2, 2005, 6:39 am
 

It's just Ohm's law, with different units:

I = (142-70)/(1/3+9.8+2/3) = 6.7 Btu/h, so Tw = 70 + 6.7x2/3 = 74.4 F,
and Ts = 74.4 + 6.7x9.8 = 139.7.

Nick


Posted by John on March 2, 2005, 4:47 pm
 If you get a chimney fire the temp is gong to be much higher than 600 F
I have seen stove pipe turn cherry red just from a wood stove's draft
out of control





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