Posted by Curbie on February 7, 2011, 6:53 pm
On Mon, 7 Feb 2011 11:09:59 -0700, Steve Ackman
> Jumping in a bit late here, and not having read the
>entire thread...
> You're way overcomplexicatizing things given some
>of your reading audience.
>950 ft2 roof / 177 ft2 pool = 5.37, so for every inch
>that falls on his roof, his pool sees something less
>than 5.37 (subtracting whatever undefined amount
>overflows the gutters). Add the inch that falls
>directly into the pool, and 1" of rainfall adds
>something less than 6.37" to the pool.
The normal rain fall for the rainiest month (August) in Tampa is 7.6".
http://www.rssweather.com/climate/Florida/Tampa/
No matter if you use which simple arithmetic is used it still takes 3"
of rain in one day, not accounting for rain run-off, splash-off and
wind blow-off and not collected, (or half the rain fall of the
rainiest month of the year) to collect the 2000 gallons claimed, -
which is 1) non-sense and 2) not helpful to anyone thinking about
building a cistern for themselves.
Curbie
Posted by daestrom on January 30, 2011, 2:16 pm
On 1/28/2011 16:39 PM, Jim Rojas wrote:
> Curbie wrote:
>>> So what you are saying that it is impossible to collect 1000 gallons of
>>> rain water in just one day of rain? You obviously never been Florida.
>> I'm just saying .5" of rain isn't a normal day's rain and to convert a
>> normal day's rain (in August the rainiest month of the year for Tampa)
>> of .25" you or anyone else would need an 8,400 ft2 house footprint!
>>
>> I'm also saying you should try to get facts straight so you don't
>> mislead readers, which is a bad habit of yours and if people are
>> interested in this idea, they get a lot further along doing the
>> numbers.
>>
>> Your view of what is obvious, is about as factual as most other things
>> you've said, I lived in Deerfield Beach FL for about 30 years.
>>
>> Good message, shaky messenger.
>>
>> Curbie
>>
>>
> I went to 3 different online pool volume calculators. Each one stated
> that a 15ft round pool that is 18 inches deep (amount of rain I
> collected) comes out to 2000 gallons. That's alot more that I expected.
> So one normal .5 inch of rainfall is all I need in a month to keep my
> pool topped off. Though I may need more due to summer heat evaporation.
> I will keep you all posted.
> Jim Rojas
The roof area you mentioned was about 950 ft^2. Add to that the pool
itself (area 176 ft^2) for a collection surface of 1126 ft2.
2000 gallons is 267 ft^3 of water, divided by the area of collection
works out to almost 3 inches of rain.
If you collected six inches of water in an open bucket placed away from
any structures, you did indeed have six inches of rain (at least in your
general neighborhood). That's basically what a rain-gauge is. If the
sides are straight and parallel, the depth is a direct measurement.
Most rain-gauges have tapered sides to make it easier to measure small
amounts, but that doesn't sound like a problem in your case.
daestrom
Posted by Jim Rojas on January 30, 2011, 3:32 pm
daestrom wrote:
> On 1/28/2011 16:39 PM, Jim Rojas wrote:
>> Curbie wrote:
>>>> So what you are saying that it is impossible to collect 1000 gallons of
>>>> rain water in just one day of rain? You obviously never been Florida.
>>> I'm just saying .5" of rain isn't a normal day's rain and to convert a
>>> normal day's rain (in August the rainiest month of the year for Tampa)
>>> of .25" you or anyone else would need an 8,400 ft2 house footprint!
>>>
>>> I'm also saying you should try to get facts straight so you don't
>>> mislead readers, which is a bad habit of yours and if people are
>>> interested in this idea, they get a lot further along doing the
>>> numbers.
>>>
>>> Your view of what is obvious, is about as factual as most other things
>>> you've said, I lived in Deerfield Beach FL for about 30 years.
>>>
>>> Good message, shaky messenger.
>>>
>>> Curbie
>>>
>>>
>>
>> I went to 3 different online pool volume calculators. Each one stated
>> that a 15ft round pool that is 18 inches deep (amount of rain I
>> collected) comes out to 2000 gallons. That's alot more that I expected.
>> So one normal .5 inch of rainfall is all I need in a month to keep my
>> pool topped off. Though I may need more due to summer heat evaporation.
>> I will keep you all posted.
>>
>> Jim Rojas
> The roof area you mentioned was about 950 ft^2. Add to that the pool
> itself (area 176 ft^2) for a collection surface of 1126 ft2.
> 2000 gallons is 267 ft^3 of water, divided by the area of collection
> works out to almost 3 inches of rain.
> If you collected six inches of water in an open bucket placed away from
> any structures, you did indeed have six inches of rain (at least in your
> general neighborhood). That's basically what a rain-gauge is. If the
> sides are straight and parallel, the depth is a direct measurement. Most
> rain-gauges have tapered sides to make it easier to measure small
> amounts, but that doesn't sound like a problem in your case.
> daestrom
Ah, I see. The bucket is tapered. Wide on top, 1/2 the diameter on
bottom. It is a small garbage pail. So I guess I did get 3 inches of
rain that morning. The pool filled up within 3-4 hours.
Jim Rojas
Posted by Curbie on January 30, 2011, 7:54 pm
daestrom,
Valid point, but even adding an extra 167ft2 the pool area collects,
this system only collects 350 gallons on an abnormal .5" daily
rainfall to fill a 2000 gallon deficit, non-sense.
So to get this part of his fairy-tail to come true we need to boost
the rainfall to 3" per day, or almost half of total average monthly
rainfall for the wettest month of the year needs to fall on one day to
make this part of fairy-tail come true. More non-sense.
Curbie
>The roof area you mentioned was about 950 ft^2. Add to that the pool
>itself (area 176 ft^2) for a collection surface of 1126 ft2.
>2000 gallons is 267 ft^3 of water, divided by the area of collection
>works out to almost 3 inches of rain.
>If you collected six inches of water in an open bucket placed away from
>any structures, you did indeed have six inches of rain (at least in your
>general neighborhood). That's basically what a rain-gauge is. If the
>sides are straight and parallel, the depth is a direct measurement.
>Most rain-gauges have tapered sides to make it easier to measure small
>amounts, but that doesn't sound like a problem in your case.
>daestrom
Posted by Jim Rojas on January 30, 2011, 8:10 pm
Curbie wrote:
> daestrom,
> Valid point, but even adding an extra 167ft2 the pool area collects,
> this system only collects 350 gallons on an abnormal .5" daily
> rainfall to fill a 2000 gallon deficit, non-sense.
> So to get this part of his fairy-tail to come true we need to boost
> the rainfall to 3" per day, or almost half of total average monthly
> rainfall for the wettest month of the year needs to fall on one day to
> make this part of fairy-tail come true. More non-sense.
> Curbie
>> The roof area you mentioned was about 950 ft^2. Add to that the pool
>> itself (area 176 ft^2) for a collection surface of 1126 ft2.
>>
>> 2000 gallons is 267 ft^3 of water, divided by the area of collection
>> works out to almost 3 inches of rain.
>>
>> If you collected six inches of water in an open bucket placed away from
>> any structures, you did indeed have six inches of rain (at least in your
>> general neighborhood). That's basically what a rain-gauge is. If the
>> sides are straight and parallel, the depth is a direct measurement.
>> Most rain-gauges have tapered sides to make it easier to measure small
>> amounts, but that doesn't sound like a problem in your case.
>>
>>
>> daestrom
I currently use only 6K gallons a month of city water. Why is this so
hard for you to accept? I only plan to use the collected water to wash
clothes, flush the toilets, and maybe wash the cars.
Jim Rojas
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>entire thread...
> You're way overcomplexicatizing things given some
>of your reading audience.
>950 ft2 roof / 177 ft2 pool = 5.37, so for every inch
>that falls on his roof, his pool sees something less
>than 5.37 (subtracting whatever undefined amount
>overflows the gutters). Add the inch that falls
>directly into the pool, and 1" of rainfall adds
>something less than 6.37" to the pool.