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Re: GFX vs home brew - Page 21

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Posted by daestrom on April 18, 2006, 9:01 pm

Well, if by 'spiral' you mean some sort of serpentine.

Since the pipe is nominally 4", to get a spiral (even a 'flat spiral'), you
need at least 8" where one turn crosses over the other ;-)

7' diameter coils for 100' total length means about 18 turns.  Coiled in a
vertical stack and then 'shoved' off to the side to spread the coils out
nearly flat would take a floor space 7' wide and about 72' long (18 turns
spaced about 4' apart).  That's a tad much floor space for most folks ;-)


Posted by daestrom on April 18, 2006, 9:12 pm

No, that can't be right :-(

7' diameter coils for 100' total length is only about 4.5 turns.  Spread out
in a flat spiral, that would be 7' wide and about 16' feet long.  Still a
fair piece of real-estate.


Posted by nicksanspam on April 18, 2006, 9:47 pm

A mere disk, only 1 layer tall.

... with no crossings.

I think we have some posting delay, and you musta missed this posting:

Article 111798 of alt.energy.homepower:
From: nicksanspam@ece.villanova.edu
Newsgroups: alt.home.repair,alt.solar.thermal,alt.energy.homepower,
Subject: Re: GFX vs home brew
Date: 15 Apr 2006 15:46:00 -0400
Organization: Villanova University

The 4" tall spiral hung under a basement ceiling would be about 7'
in diameter.  The 6' tall coil would occupy a 2.7' floor circle.
It seems simpler to install and might have better stratification.

10 PI=4*ATN(1)
20 D=4.25'pipe OD (inches)
30 L0'pipe length (feet)
40 DI=2'coil ID (feet)
50 DO=DI+2*D/12'coil OD (feet)
60 CI=PI*DI'inner circumference (feet)
70 NT=L/CI'number of turns
80 H=NT*D/12'coil height (feet)

 4.25          2             2.708333      15.91549      5.636738

10 PI=4*ATN(1)
20 D=4.25'pipe OD (inches)
30 L0'pipe length (feet)
40 A=D*L/12'pipe area (ft^2)
50 DI=2'flat spiral ID (feet)
60 DO=2*SQR(A/PI+(DI/2)^2)'spiral OD (feet)
70 NT*(DO-DI)/2/D'number of turns

 4.25          2             7.006704      7.068288


Posted by daestrom on April 18, 2006, 11:29 pm

Yah, I think so.

I was thinking of a helical arrangement, you're talking about a spiral like
a phonograph groove.

Yes, it could be that small.


Posted by dold on April 19, 2006, 1:14 am

What do you do when you get to the center of the phonograph?
Isn't there still at least one crossover needed?

Clarence A Dold - Hidden Valley (Lake County) CA USA  38.8,-122.5

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