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Posted by Martin and Mellisa Rimmer on October 9, 2004, 1:13 pm
 
Hi

I live in kalgoorlie in Westren Australia, on the edge of the desert,
similar weather to Nevada or Utah desert for you americans, and want to
build my own solar pool heater.  they are about A$000 to have installed in
OZ.

I am pretty well educated and could do some sums myself if somene could send
me some equations that I may use to size the equipment and then anyone that
has some design  ideas,concepts, philosophies would be really helpful.

We have a very hot summer, but my pool has a lot of shade hence can not use
it for much of the year.

Waiting eagerly for some response.

Cheers

Martin



Posted by N. Thornton on October 9, 2004, 8:38 pm
 

A standard, easy to make, low cost solar pool panel would be a large
coil of hose under a sheet of polythene, plus pump. A bit more idea of
what youre looking for would help, eg cheap and functional like
hosepipe, swanky and flash or invisible for a smart complex, amount of
heat needed, etc.

NT

Posted by john on October 10, 2004, 9:08 am
 yea  12 or 25 mm  hose under glass  with a pump supplying a bit of
circulation  if you can do it up a wall   properly  then the hot water rises
allowing cold in the bottom     u dont have to use glass    a couple of  the
roof sheets would do the same


Posted by nicksanspam on October 10, 2004, 12:48 pm
 


Very dry, so you want the pool covered most of the time to reduce heat
loss by evaporation... 1170 Btu/ft^2 of sun falls on the ground on an
average 53.2 F October day with an average daily max of 66.1.
 

The polythene won't help much, given its 10% solar transmission loss and
the hose which already reduces evaporation loss and the poor warm-air to
hose conductance and the low water collection temp.

You might put 2 layers of UV-treated polytunnel film on a near-flat surface
in the sun and pump water between them. If a square foot of 75 F covered
pool loses 24h(75-53.2)1ft^2/R1 = 523 Btu/day of heat and a square foot of
drainback heater gains 0.9x1170 = 1053 Btu and loses 6h(85-53.2)1ft^2/R1
= 862, you need 523/862, ie 61% of the pool surface as heater. In full sun,
keeping the temp rise below 20 F requires at least 10 pounds of water per
hour (0.02 gpm) per square foot of heater.

Nick


Posted by john on October 10, 2004, 11:01 pm
 heres an ugly solloution   im in the gem fields out of Emerald  and to stop
evaporation we use 2 liter soda bottles on the top of our water tanks  not
pretty  but seems to work
swimming in them would give you added exercise i recon
take the labels off first lol



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